The centre of mass of the shaded portion of the disc is : (The mass is uniformly distributed in the shaded portion) :
A
to the left of A
B
to the left of A
C
to the right of A
D
to the right of A
Text Solution
Verified by ExpertsThe correct answer is:
A
A 1 = π R 2 A 2 = 
x 1 = 0 x 2 = 
x cen = 
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